# physic physic ?????

• A ball is kicked directly toward a fence from a point 32 meters away as shown below. The velocity of the ball as it leaves the kicker's foot is 20m/s at an angle of 37 degrees above the horizontal. The top of the fence is 2.5 meters high. The ball hits nothing while in flight and air resistance is negligible. Will the ball hit the fence? If so how far below the top of the fence will it hit? If not, how far above the top of the fence will it pass?

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• ok so it like a right-angled triangle...

u have the measurement for the adjacent which is 32 meters ... and the opposite is 2.5 meters

they also gave u the angle of the ball is 37 degrees ... use the formula of cosine to find the hypotenuse side ...

the formula is cos (the degree ) = adjacent (m)/ hypotenuse (m) => so to find the hypotenuse => adjacent ( m) / cos ( the degree) = hypotenuse ( m)

when u already have the measurements for the adjacent side n hypotenuse side .. use the formula

a^2 + b^2 = c^2 to find the measurement of the adjacent side

c = hypotenuse side n a = adjacent side => so the formula to find adjacent side is => c^2 - a^2 = b^2

once u got the answer for it ... compare it with the 2.5 meter ... u kno the rest

(btw, i tried n got something like 26.8 so it fly over the fence like 24.3 m . im not sure it the rite answer cuz i got no calculator ... .. )

good luck ok ...

• uhm, use these formulas to solve

X=V x0 T
Y=1/2gT 2 + V y0 T + Y 0

• sao chú mltr gì cũng biết vây